Üslü sayılarla ilgili çözümlü sorular
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<td>Soru1:</td>
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<td>`2^{3}.2^{5}.2^{7}=?`</td>
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<td>Çözüm:</td>
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<td>`2^{3}.2^{5}.2^{7}=2^{3+5+7}=2^{15}`</td>
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<td>Soru2:</td>
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<td>`\frac{5^{7}.5^{4}}{5^{2}}=?`</td>
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<td>`\frac{5^{7}.5^{4}}{5^{2}}=\frac{5^{7+4}}{5^{2}}=\frac{5^{11}}{5^{2}}=5^{11-2}=5^{9}`</td>
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<td>Soru 3:</td>
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<td>`\frac{-2^{3}+(-2)^{3}}{-2^{2}-(-2)^{5}}=?`</td>
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<td>Çözüm :</td>
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<td>`\frac{-2^{3}+(-2)^{3}}{-2^{2}-(-2)^{5}}=\frac{-8+(-8)}{-4-(-32)}=\frac{-16}{28}=\frac{-4}{7}`</td>
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<td>Özellik:</td>
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<td>`a^{-n}=\frac{1}{a^{n}},`</td>
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<td>`(\frac{a}{b})^{-n}=(\frac{b}{a})^{n}`</td>
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<td>Soru 4:</td>
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<td>`\frac{(\frac{1}{2})^{-3}+3^{-1}}{(\frac{3}{2})^{-2}}=?`</td>
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<td>Çözüm :</td>
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<td>`\frac{(\frac{1}{2})^{-3}+3^{-1}}{(\frac{3}{2})^{-2}}=\frac{2^{3}+(\frac{1}{3})}{(\frac{2}{3})^{2}}=\frac{8+(\frac{1}{3})}{\frac{4}{9}}=\frac{\frac{25}{3}}{\frac{4}{9}}=\frac{25}{3}.\frac{9}{4}=\frac{225}{12}=\frac{75}{4}`</td>
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